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Exemple Ratio 2 = 6.021 dB

Voltage: $\mathrm{dB}=20{\log }_{10}\left(\mathrm{ratio}\right)$ — Power: $\mathrm{dB}=10{\log }_{10}\left(\mathrm{ratio}\right)$. Power goes as voltage squared, which is the whole reason for the 20 against the 10. A bench dB question is usually absolute, not relative — "what's 30 dBm in watts" — which Absolute level below answers directly.