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Divisor de corriente

Ejemplo I1 = 8.246 mA through R1 — I2 = 1.754 mA through R2

Fórmula

I_{1} = I_{in} \times \frac{R_{2}}{R_{1} + R_{2}}

Con los valores por defecto

8.246 mA = 10 mA \times \frac{4.7 kΩ}{1 kΩ + 4.7 kΩ}

Two parallel resistors split an incoming current in inverse proportion to their resistance — the smaller resistor carries the larger share. $I_{1} = I_{in} \times \frac{R_{2}}{R_{1} + R_{2}}$

Lo que introduces

Iin (A)
R1 (Ω)
R2 (Ω)

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